Hey guys so i need help with maths D; the question is f(x)=3x^2(1-2x)^5. Find f(1) and f '(1) It's annoying me soooo much :/

(f(x) * g(x))' = f'(x)*g(x) + f(x)*g'(x) (f(g(x)))' = f'(g(x))*g'(x) f(1) = 3*12*(1 - 2*1)5 = -3 f'(x) = 6x(1 - 2x)5 + 3x*(1 - 2x)4*5*(-2) f'(1) = -36 I think.