Maths Help?

[Hellow]

Hey guys so i need help with maths D;
the question is f(x)=3x^2(1-2x)^5. Find f(1) and f '(1)
It's annoying me soooo much :/

 

[mcp2]

Product rule my man and chain rule for this bit '(1-2x)^5'

 

[Veho]

(f(x) * g(x))' = f'(x)*g(x) + f(x)*g'(x)
(f(g(x)))' = f'(g(x))*g'(x)



f(1) = 3*12*(1 - 2*1)5 = -3



f'(x) = 6x(1 - 2x)5 + 3x*(1 - 2x)4*5*(-2)

f'(1) = -36


I think.