The hardest easy geometry problem.

[Veho]

HERE: http://img148.imageshack.us/my.php?image=freeeeezwv7.jpg

Um, ADEB isn't a parallelogram, none of its sides is parallel to any of the others.

EDIT: Nope, even with quadrilateral, there's no rule saying opposite angles add up to 180°.

 

[FrEEz902]

HERE: http://img148.imageshack.us/my.php?image=freeeeezwv7.jpg

Um, ADEB isn't a parallelogram, none of its sides is parallel to any of the others.

EDIT: Nope, even with quadrilateral, there's no rule saying opposite angles add up to 180°.

Ha? o.O? Err, are you sure x.X? Then i guess i've been taught wrong at school :

 

[Veho]

I think i remember somewhere if you cut off all the corners of a parallellogram, and put them together, it will be a perfect 360 degrees.

The sum of all the inside angles of a parallelogram is 360, true, but this isn't a parallelogram so that doesn't apply here.

 

[moozxy]

Ye I've never heard that rule before either. And yes all angles in any quadrilateral add up to 360.

 

[FrEEz902]

Ye I've never heard that rule before either. And yes all angles in any quadrilateral add up to 360.

if that's true, then shouldn't the opposite sides add up to 180? Or is that only if it's parallel...

GAH anyhow i fail :

 

[Veho]

And yes all angles in any quadrilateral add up to 360.

DOH!! Totally forgot about that one...

Okay, yes, but that leaves us with 360 = 360, because the x cancels itself out in the equation.

We're all missing something here.

 

[FrEEz902]

Apparently here is a hint: http://thinkzone.wlonk.com/MathFun/Triangle1Hint1.htm

Edit: I *THINK* i got it... If we draw a perpendicular line from DE in the 'x' triangle, and it cuts X by half, then we can get 1/2 x =180-(90+50)=40??.

But then that would mean X=40*2=80. And that is definitely wrong.

EDIT: nvm, it won't be perpendicular if we did that.

 

[Twiffles]

I'll attemp this later, that is if the answer isn't found by then. I hated Geometry and I'm hating Calculus even more. >.>

 

[FrEEz902]

I googled and found a solution...yet i'm too scared to look at it

.

 

[moozxy]

Noooo if you post it, post it in spoilers.. I kinda wanna find the solution by myself now

 

[FrEEz902]

Noooo if you post it, post it in spoilers.. I kinda wanna find the solution by myself now

i won't post it

. I *think* we need to draw an extra line. Where and why i have no idea.

 

[moozxy]

Ye after you posted that I've drawn two extra lines.. I think I can get the answer.. I'm not sure.

 

[TGBoy]

This was where i found the solution. This is one way. I guess there must be other methods.

One Solution

 

[xcalibur]

Ye I've never heard that rule before either. And yes all angles in any quadrilateral add up to 360.



if that's true, then shouldn't the opposite sides add up to 180? Or is that only if it's parallel...

GAH anyhow i fail :

 

[FrEEz902]

Ye I've never heard that rule before either. And yes all angles in any quadrilateral add up to 360.



if that's true, then shouldn't the opposite sides add up to 180? Or is that only if it's parallel...

GAH anyhow i fail :

 

[Verocity]

I did stuff like that my freshman year in High school, I'm now in Algebra 2 which is a lot harder.

EDIT: and starting January ill be doing Algebra 3

 

[Veho]

I did stuff like that my freshman year in High school, I'm now in Algebra 2 which is a lot harder.

...right. Now solve this.

 

[moozxy]

While you might be learning more difficult methods of solving problems, this uses simple rules of geometry to create this monster of a puzzle, hence the name 'Hardest easy geometry problem'

 

[Verocity]

I did stuff like that my freshman year in High school, I'm now in Algebra 2 which is a lot harder.

...right. Now solve this.

Yeah, this is tough... x=20 though.

It all adds up to be 180...

 

[dib]

Hahahahaha, that's an excellent problem. Spoiler solution:

There are multiple solutions that can fulfill the conditions of the triangle, allowing x to be just about anything