post here funny pictures

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5DIbkuP.jpg

+1 for trying..
 
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Yep, that's not how it works..

Well, no. That's not how this works. The question doesn't imply that this is how it works. Sometimes a correct solution to a math problem is "not enough information" or "is not a factor".
The duration of Beethoven's 9th is constant (shut up), and is not a function of the number of players; f(x)=A where A is a constant. So the answer is:

T(P)=40;
T(120)=T(60)=40.

This is how it works.
 
Well, no. That's not how this works. The question doesn't imply that this is how it works. Sometimes a correct solution to a math problem is "not enough information" or "is not a factor".
The duration of Beethoven's 9th is constant (shut up), and is not a function of the number of players; f(x)=A where A is a constant. So the answer is:

T(P)=40;
T(120)=T(60)=40.

This is how it works.
Maybe.. if it were a "math" problem.
Definitely not if it was about music, or music recreation/ performance.. :sleep:
 
Maybe.. if it were a "math" problem
Definitely not if it was about music, or music recreation/ performance.. :sleep:
Well... teeeechnically....
There is a limit to a human being's capability to play notes, and thus upper limit to the tempo of a music piece so there is a theoretical limit at which people can perform notes and switch chords (before the violin bursts into flames), but if we separate the chords for each instrument into two/three/four players, and have each player play every second/third/fourth note, you can multiply the speed by that factor, limited only by the capability to synchronize and coordinate at those speeds.

But I digress.
Here's the whole worksheet that included the above problem:

RtgJT9D.jpg


It's math.
 

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