C - file not opening

[Monado_III]

I'm going to do a complete rewrite my sad excuse of an emulator that doesn't even work and I'm having some trouble with opening the file. It should first open zenity (which works), then copy the output of zenity, which is the path to whatever file they chose, then parse the output and put backslashes in front of spaces (which works), but whenever I actually try to open the file (a file that does exist) it always fails, I looked around a bit more and found this so I commented out the

path[n++] = '\\';

line but to no avail. Can anyone offer some advice as to what I'm doing wrong?

Spoiler: code

#include <stdlib.h>
#include <stdio.h>
#include <string.h>

char * select_file(void)
{
    FILE *fp = popen("zenity --file-selection --title=\"Choose Gameboy Rom\"", "r");

    static char path[1024];
    memset(path, 0, sizeof(path));

    if(fp == NULL)
    {
        printf("Failed to run command, make sure you have zenity installed!\n" );
        exit(1);
    }
    fgets(path, sizeof(path), fp);
    pclose(fp);

    char path_copy[256];
    strcpy(path_copy, path);

    int n = 0;
    for(int i = 0; i < sizeof(path); i++)
    {
        if(path_copy[i] == ' ')
        {
            path[n++] = '\\';
        }

        path[n++] = path_copy[i];
    }

    return path;
}

int main(void)
{
    FILE * fp = NULL;
    char file_to_open[1024];
    strcpy(file_to_open, select_file());
    printf("%s", file_to_open);
    fp = fopen(file_to_open, "r");
    if (fp == NULL)
    {
        perror("Error opening file: ");
    }

    return 0;
}

 

[TheZoc]

From the looks of it, your code reminds me of unix/linux code, yet you're using windows paths.

Try using '/' in place of '\\' and see if it works

 

[Monado_III]

From the looks of it, your code reminds me of unix/linux code, yet you're using windows paths.

Try using '/' in place of '\\' and see if it works

the '\'s are for spaces (think escape sequences), the actually path that you get from printf is something like /home/*user*/somedir/some\ file.txt, I'm not sure if the backslashes are needed in C but it doesn't seem to make a difference as nothing opens either way

 

[spoonm]

the '\'s are for spaces (think escape sequences), the actually path that you get from printf is something like /home/*user*/somedir/some\ file.txt, I'm not sure if the backslashes are needed in C but it doesn't seem to make a difference as nothing opens either way

The escape slashes are not needed. I just created a file called "test file" with the contents:

Can I open this file? Can I?
Will it fail, my while?

I like coconut water.

, then wrote, compiled and ran the following:

#include <stdio.h>
#include <stdlib.h>

int
main(void)
{
    FILE *fp = NULL;
    int c;

    if ((fp = fopen("test file", "r")) == NULL)
    {
        perror("Error opening file");
        exit(1);
    }

    while ((c = fgetc(fp)) != EOF)
        putchar(c);

    fclose(fp);

    return EXIT_SUCCESS;
}

And it's worked fine: