Help with python

[raystriker]

So here's the thing, I want to convert a base 10 integer and output it in base 16 as a string-
Here's what I have:

#number n in base ten to base b=16
def d(n,b):
    ans=" "
   
    quotient=n/b

    while quotient !=0:
       
        remainder=(quotient % b)
        if remainder < 10:
            ans= str(remainder) + ans
        elif remainder == 10:
            ans= 'A' + ans
        elif remainder == 11:
            ans= 'B' + ans
        elif remainder == 12:
            ans= 'C' + ans
        elif remainder == 13:
            ans= 'D' + ans
        elif remainder == 14:
            ans= 'E' + ans
        elif remainder == 15:
            ans= 'F' + ans
       
        quotient=(quotient / b)
       
    return str(ans)
   
print(d(200,16))
print(d(689,16))

When I run the program, I get some weird output.
Where am I going wrong?
Plz help.
Thanks.

 

[zoogie]

Replace every / with //
that forces integer division

you can get away with / in py -2 but not py -3

 

[raystriker]

Replace every / with //
that forces integer division

you can get away with / in py -2 but not py -3

Thanks, that worked!
Does my algorithm seem right?
My output is:

C
2B

but it should be:

C8
2B1

 

[sarkwalvein]

Thanks, that worked!
Does my algorithm seem right?
My output is:

C
2B

but it should be:

C8
2B1

No, it is wrong because you are avoiding to check the last remainder.
You know, e.g.
If you did d(5), then the first check would do:
quotient = 5 // 16

and that is 0, so it will not get inside the while and deal with the 5, in other words it will print nothing.

If you want I can think of some suggestion to fix that.

 

[raystriker]

No, it is wrong because you are avoiding to check the last remainder.
You know, e.g.
If you did d(5), then the first check would do:
quotient = 5 // 16

and that is 0, so it will not get inside the while and deal with the 5, in other words it will print nothing.

If you want I can think of some suggestion to fix that.

Thanks, I'll try and work something out!

 

[raystriker]

No, it is wrong because you are avoiding to check the last remainder.
You know, e.g.
If you did d(5), then the first check would do:
quotient = 5 // 16

and that is 0, so it will not get inside the while and deal with the 5, in other words it will print nothing.

If you want I can think of some suggestion to fix that.

Seems that my first number's not being printed( under the first if statement), help?

 

[sarkwalvein]

#number n in base ten to base b=16
def d(n,b):
    if n==0:
       return str("0")
  
    ans=" "
    while n !=0:
   
        remainder=(n % b)

        if remainder < 10:
            ans= str(remainder) + ans
        elif remainder == 10:
            ans= 'A' + ans
        elif remainder == 11:
            ans= 'B' + ans
        elif remainder == 12:
            ans= 'C' + ans
        elif remainder == 13:
            ans= 'D' + ans
        elif remainder == 14:
            ans= 'E' + ans
        elif remainder == 15:
            ans= 'F' + ans
   
        # You are always printing the less significant digit of n
        # So iterative, you need to remove from n the less significant digit
        # (that is divide by the base), and start the loop again, until n is 0.
        n = n // b      # I know the variable name could be better thought, I leave that to you.

    return str(ans)
 
print(d(200,16))
print(d(689,16))

Try this.

 

[sarkwalvein]

Also, I guess you are making this function just to try doing it yourself, otherwise you can use the standard function format to accomplish the same (e.g. format(200,'X') would do the same)

 

[raystriker]

Thanks a lot!