# Want to help?

Discussion in 'General Off-Topic Chat' started by Golfman560, Aug 31, 2009.

# Want to help?

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1. ### Golfman560TheRapist.com

Member
Dec 29, 2008
Living with seals
Okay so I've got a math problem. Pretty sure it has a typo but whatever, its due Wednesday and I'll probably email the teacher.

Here's how it goes:

If f(x)=3x^2 - 2x + 7 and a != (Does not equal) x, write [f(x) - f(a)]/(x - a) as a single polynomial in terms of a and x.

At first I thought it was supposed to be [f(x-h) - f(x)]/h) But that would be a huge typo.

Anyone want to help?

2. ### VehoThe man who cried "Ni".

Former Staff
Apr 4, 2006
Zagreb
It equals 3x + 3a - 2

[f(x) - f(a)] = 3x2 - 2x + 7 - 3a2 + 2a - 7

= 3(x2 - a2) - 2(x - a)

= 3(x + a)(x - a) - 2(x - a)

Divide that by (x-a) and you get the above result.

3. ### Golfman560TheRapist.com

Member
Dec 29, 2008
Living with seals
Thanks, but all I really needed was this. I went somewhat braindead last night and also forgot how to graph on my calculator.

Well now to do it and check my answer with yours. Thanks Veho.

4. ### ACK06Member

Newcomer
Aug 10, 2009
Intro to Calc?

5. ### Golfman560TheRapist.com

Member
Dec 29, 2008
Living with seals
Well its the summer homework so kinda, more like a refresher of the last few years. I'll be starting Calc Wednesday.

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