Process Calculus

Discussion in 'General Off-Topic Chat' started by SinHarvest24, May 24, 2011.

May 24, 2011

Process Calculus by SinHarvest24 at 6:34 PM (1,533 Views / 0 Likes) 37 replies

  1. SinHarvest24
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    Ok, i started classes a few days ago and we did something called Process Calculus. We're learning how to make/change the subject of the equation. I'm a bit confused on a few things.

    Say i have this: r - t * a/b = k (make "b" the subject, a/b being a fraction)

    Answer : r - t * a/b = k
    r * a/b = k + t
    a/b = k + t - r
    a = b(k + t - r)
    a/k+t-r = b



    Is that correct?

    When i was doing it in class i was moving the wrong unknown first and ended up doing crap most of the time.

    Any tips?

    You can also give me a question, i like to practice. [​IMG]
     


  2. smealum

    Member smealum growing up sucks.

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    r - t * a/b = k
    rb - ta = kb
    -ta = b(k-r)
    b = - ta/(k-r)

    Hope this helps.
     
  3. Wizerzak

    Member Wizerzak Because I'm a potato!

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    I'm not 100% sure but i'm pretty certain that with the bit in bold you can't do that.... remember BIDMAS (or BODMAS w/e)
     
  4. SinHarvest24
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    Member SinHarvest24 Shiroyasha

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    Well, i'm just following the same steps i learned in class. Can anyone else confirm that i can't do that?
    Do you agree with the first poster?
     
  5. Wizerzak

    Member Wizerzak Because I'm a potato!

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    possibly right, i can't see how he did the bit in bold but it's possibly correct.

    I recommend this site which gives free, online, live tutoring. I've used it a few times and the teachers there are great. Say Wizzerzak told you about it, they might remember me.
     
  6. Cuelhu

    Member Cuelhu КУ!

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    r - t . a/b = k
    r - ta/b = k
    r = ta/b + k
    r - k = ta/b

    (r - k)b = ta

    b = ta/(r - k)
     
  7. Wizerzak

    Member Wizerzak Because I'm a potato!

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    Yes, I see now. That's definitely right.
     
  8. SinHarvest24
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    like what you did there, can you give me some tips on when do i do those things. Which one do i move first and which not to.
     
  9. The Pi

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    r - t * a/b = k Write it down first
    rb - ta = kb Knock out any and all fractions
    rb - kb = ta Move all terms containing the variable you're trying to solve for to the left and everything else to the right
    b (r - k) = ta Single out the variable
    b = ta / (r - k) Solve for the variable

    Simples [​IMG]
     
  10. SinHarvest24
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    Hit me a question/s lemme see if i got this.
     
  11. Jamstruth

    Member Jamstruth Secondary Feline Anthropomorph

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    This isn't Calculus. This is algebra.

    r- t * a/b = k
    (r - t)(a/b) = k
    (a(r - t))/b = k
    a(r - t) = kb
    (a(r - t))/k = b

    In the way you wrote it it would be
    (r - t) * (a/k)

    I'm sure that's how its done if I'm reading the equation right. I much prefer using brackets than * symbols in these equations. The problem when you're making up things like this is how to write them so you don't get confused. Its quite possible all of us have right answers, just not for the same equation.

    Anyway try this one

    A - B(C - D) = (E - F)/G
    Rearrange for F

    Edit: Looking at the equation again it could be this. (Damn BODMAS maths does not translate to text well)

    r - t(a/b) = k
    - t (a/b) = k - r
    t (a/b) = r - k
    a/b = (r - k)/t
    b/a = t/(r - k)
    b = at/(r - k)
     
  12. The Pi

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    C = (5 (F - 32))/9

    Make F the subject.
     
  13. s4mid4re

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    if you distribute b(k-r) it becomes bk - br or kb - rb.

    r - t * a/b = k
    rb -ta = kb
    -ta = kb - rb kb - rb is replaced by b(k-r) to get rid of multiple unnecessary steps.
    -ta = b(k-r)
    -ta/(k-r) = b

    this looks simpler imo, though:

    r -ta/b = k subtract r from both sides
    -ta/b = k-r multiply both sides by b
    -ta = (k-r)b divide both sides by (k-r)
    -ta/(k-r) = b done

    just to not cause confusion, -ta/(k-r) = ta/(r-k)
     
  14. SinHarvest24
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    A - B(C - D) = (E - F)/G
    Attemp 1
    Warning: Spoilers inside!

    Attemp 2
    Warning: Spoilers inside!
     
  15. s4mid4re

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    I'm assuming that you're solving for F here.
    This is what I got:
    Warning: Spoilers inside!
    I don't know if mine is correct, so I can't really say that yours is incorrect. [​IMG]

    Can somebody check over our work?
     
  16. Jamstruth

    Member Jamstruth Secondary Feline Anthropomorph

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    Attempt Pi's first, mine was way too confusing now I read it through... I've been doing too much really hard calculus and algebra lately (adv higher maths [​IMG] )

    A-B(C - D) = (E - F)/G original equation
    G(A-B)(C-D) = E - F Multiply both sides by G
    G(A - B)(C - D) - E = -F Take E from both sides
    F = E - G(A - B)(C - D) Multiply both sides by -1
    Edit: THIS IS INCORRECT!!! Spot the error and win a bowl of nothing.

    The following solution IS right
    A - B(C-D) = (E - F)/G
    G(A - B(C-D)) = E-F Multiply both sides by G
    -F = G(A-B(C-D)) - E SUbtract E from both sides
    F = E - G(A-B(C-D)) Multiply both sides by -1
    This is the equation's simplest form.

    Unless the question specifically asks you to I wouldn't bother multiplying out any brackets you are given. If I now gave you the values of A, B, C, D, E and G then it would be a lot easier to work from this form to find F than the fully multiplied form.
    Since I don't really know the level you work to your best bet is to look in your textbook and try and attempt a few questions, if you want then we'll check them.
    Its a LOT easier to understand handwritten maths so if you do do this then it would be best to do it on paper and take a photo of your work to upload. We'll know the exact form of the equation you had at the start.
     
  17. SinHarvest24
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    C = (5 (F - 32))/9
    9C = 5 (F - 32)
    9C/5 = F - 32
    9C/5 + 32 = F


    is that right? [​IMG]


    @Jamstruth - i see what you did there and understand that, that is right.
     
  18. Issac

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    A + B - (C(D-F(G+H))) = B + 2A/C

    try that one! [​IMG]

    edit: for G
     
  19. SinHarvest24
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    A + B - (C(D-F(G+H))) = B + 2A/C

    - C(D-F(G+H)) = B + 2A/C -A - B

    D-F(G+H) = (B + 2A/C -A - B)/-C

    -F(G+H) = (B + 2A/C -A - B)/-C - D

    G+H = ((B + 2A/C -A - B)/-C - D)/-F

    G = ((B + 2A/C -A - B)/-C - D)/-F - H



    That's what i got....correction?
     
  20. Jamstruth

    Member Jamstruth Secondary Feline Anthropomorph

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    Do you mean B + (2A/C) or (B + 2A)/C?
     

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