Math problem (year 8 level, should be easy)

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KingdomBlade said:
QUOTE said:
The proof starts from the Peano Postulates, which define the natural
numbers N. N is the smallest set satisfying these postulates:

P1. 1 is in N.
P2. If x is in N, then its "successor" x' is in N.
P3. There is no x such that x' = 1.
P4. If x isn't 1, then there is a y in N such that y' = x.
P5. If S is a subset of N, 1 is in S, and the implication
(x in S => x' in S) holds, then S = N.

Then you have to define addition recursively:
Def: Let a and b be in N. If b = 1, then define a + b = a'
(using P1 and P2). If b isn't 1, then let c' = b, with c in N
(using P4), and define a + b = (a + c)'.

Then you have to define 2:
Def: 2 = 1'

2 is in N by P1, P2, and the definition of 2.

Theorem: 1 + 1 = 2

Proof: Use the first part of the definition of + with a = b = 1.
Then 1 + 1 = 1' = 2 Q.E.D.

Note: There is an alternate formulation of the Peano Postulates which
replaces 1 with 0 in P1, P3, P4, and P5. Then you have to change the
definition of addition to this:
Def: Let a and b be in N. If b = 0, then define a + b = a.
If b isn't 0, then let c' = b, with c in N, and define
a + b = (a + c)'.

You also have to define 1 = 0', and 2 = 1'. Then the proof of the
Theorem above is a little different:

Proof: Use the second part of the definition of + first:
1 + 1 = (1 + 0)'
Now use the first part of the definition of + on the sum in
parentheses: 1 + 1 = (1)' = 1' = 2 Q.E.D.

There's your proof.

tj_cool said:
(1 + 1) x 0 = 2 x 0
-> 1 + 1 = 2
Q.E.D.

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So that means that:

(685944.543 + 1043255252.435252) X 0 = 2 X 0
-> 685944.543 + 1043255252.435252 = 2

I highly doubt it.
We did this in class once.
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Bricks were shat.
 
Time for mathematical bullshit
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X=Y

So X2 = XY = Y2

So X2 - Y2 = X2 - XY

(X-Y)(X+Y) = X(X-Y)

X+Y= X

since X = Y

X+X = X

2X=X

Dividing by X

2=1
 
[title: Too many emoticons!
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]Off Topic!
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I can't believe this... From a simple 3 post topic... this topic became a hot topic just because I posted a "mistake answer"
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From that moment it started to grow with all kind of answers...
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Sorry for this...
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Peace!
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The Pi said:
Time for mathematical bullshit
happy.gif


X=Y

So X2 = XY = Y2

So X2 - Y2 = X2 - XY

(X-Y)(X+Y) = X(X-Y)

X+Y= X
since X = Y

X+X = X

2X=X

Dividing by X

2=1
You are dividing by x-y=0
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