What is the Wii ISO size?

Discussion in 'Wii - Hacking' started by Wiimm, Apr 23, 2010.

  1. Wiimm
    OP

    Wiimm Developer

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    Overall I read that the size of a single layer wii iso image is 4 699 979 776 bytes == 0x118240000 == 143432 blocks (block size=32768). This value is also supported by libwbfs.

    But a little analyze of my about 60 discs tells me, that the maximum is only 4.684.775.424 bytes == 0x1173c0000 == 142968 blocks. This value is taken from the end of the data partition. 52 discs have exact this values and the others are smaller. Only the one double layer is greater.

    My question: Is 4 699 979 776 bytes really the correct value?


    my little unix code:
    Code:
    wit dump -r SOURCE_DIR | grep 'DATA 0' | cut -c24- | sort | uniq -c
     
  2. FAST6191

    FAST6191 Techromancer

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    Been a while since I had to paste in this:
    * If the file is 4,699,979,776 bytes, it is unscrambled.
    * If the file is 4,700,012,544 bytes, it was unscrambled with unscrambler 0.4 (unscrambler adds 32,768 bytes to the file).
    * If the file is 4,736,698,368 bytes, it is a raw file and must be unscrambled.

    Dual layer had not appeared yet.

    As it pertains to your question I guess it is halfway between "correct" for some and a standard based on early dumping methods- a bit like how roms are not trimmed.
     
  3. pepxl

    pepxl GFX W!Z4RD

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    NVM
     
  4. xander150

    xander150 GBAtemp Regular

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    Did you read the post? [​IMG] Wiimm's value of 4.684.775.424 bytes == 0x1173c0000 == 142968 blocks doesn't appear in your list [​IMG]
     
  5. SanGor

    SanGor Witchhunter

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    a normal Wii disc has 2294912 sectors, dvd user data is 2048 per frame therefore

    2294912 * 2048 = 4699979776 = 0x118240000

    A full dvd frame is 2064 bytes and therefore a full raw dump is:

    2294912 * 2064 = 4736698368 = 0x11A544800

    anything else is witchcraft! [​IMG]
     
  6. ~Wiiloader~

    ~Wiiloader~ GBAtemp Regular

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    And what's the correct size of DVD9 wii ISO?