Alright.. I would be REALLY grateful if a fellow GBATemp member helped me on one Question. I'm in Algebra II but we had a Geometry/Algebra I Review sheet today... I'm really stuck on one question... Due to me dozing off during class... I will KISS your feet if you help me answer it. =P Write an equation of the line that passes through the point (2, -3) and has a slope of -1. ~This seems extremely simple, but I really have no idea how to do it... Damn my tiredness... Thanks for picking up my slack!

y=mx+b where... m= slope b= y intercept sooo... y=-1x+(-1) ps. I got the -1 by doing this: Since it HAS TO pass through the point (2,-3) i simply plugged in those values into the equation: y=-1x+? into... -3=-1(2)+? and got -1 for the y intercept. Plugged it into the equation and there ya go!

Is that Algebra II ? I read Analysis III now... like... calculate the double integral: Integral Integral lowered D for e^((y-x)/(y+z)) dxdy where D is the triangle with the corners in (0,0), (4,0) and (2,2). I hate it... exam is next Wednesday! :

damn i hate algebra... especially intergration and differention the sad thin is that those subjects actually have a use in life why do they need to be soo damn complicated?

Guys, what does integration have to do with algebra? Maybe it's the way the Canadian education system is, but Calculus is a completely different branch from Algebra. Algebra is like proving stuff, vectors and equations and rearranging them. Calculus is the one with functions, differentiation and integration.