Help with a math problem?

Discussion in 'General Off-Topic Chat' started by cheesyPOOF5, Mar 31, 2008.

  1. cheesyPOOF5
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    cheesyPOOF5 GBAtemp Fan

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    I have no idea how to do this. Can anyone help?
    [​IMG]
     
  2. OG LOCC NESS

    OG LOCC NESS GBAtemp Advanced Fan

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    Just simplify the square roots to actual numbers and solve
     
  3. cheesyPOOF5
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    cheesyPOOF5 GBAtemp Fan

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    Although that works, I know that's not what the teacher wants.
     
  4. go185

    go185 GBAtemp Regular

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    Plug it into a calculator?
     
  5. Sonicslasher

    Sonicslasher In Law we trust.

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    divide by zero?
     
  6. cheesyPOOF5
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    cheesyPOOF5 GBAtemp Fan

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    [​IMG]
     
  7. joemommasfat

    joemommasfat Member

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    just like (2^3)^4 = 2^12

    (2^sqrt(2))^sqrt(18) = 2^sqrt(36) = 2^6

    in general (a^b)^c = a^(b*c)
     
  8. cheesyPOOF5
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    cheesyPOOF5 GBAtemp Fan

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    Wow, thanks. That makes a lot of sense.
     
  9. rhyguy

    rhyguy GBAtemp Maniac

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    answer is
    Warning: Spoilers inside!
     
  10. FAST6191

    FAST6191 Techromancer

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    joemommasfat's method is correct but I suggest you learn the "power laws" as that is what this seems to want to teach.

    2^2*2^2=2^4 aka a^x.a^y = a^(x+y)
    You might like to think of this for the original purpose it was designed for.
    Mathematicians and everyone really is lazy so if something can be written in shorthand it will, not to mention a large group of letters can be very confusing at a glance.
    so a.a is written as a^2
    a.a.a is written as a^3
    a.a.a.a is written as a^4

    divided by you take instead of adding a^x/a^y = a^(x-y) (instead you might like to think of it by doing the old method of if you have a divide put it 1/number and multiply it instead and when you know 1/a = a^-1 is becomes a bit easier)

    square numbers are inverse powers
    i.e. square root of 2 is 2^1/2

    power on power gets multiplied
    (2^2)^2
    =2^4

    hope you get it sorted.