Help with a math problem?

Discussion in 'General Off-Topic Chat' started by cheesyPOOF5, Mar 31, 2008.

Help with a math problem?

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1. cheesyPOOF5GBAtemp Fan

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Apr 21, 2006
I have no idea how to do this. Can anyone help?

2. OG LOCC NESSGBAtemp Advanced Fan

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Sep 18, 2005
Just simplify the square roots to actual numbers and solve

3. cheesyPOOF5GBAtemp Fan

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Apr 21, 2006
Although that works, I know that's not what the teacher wants.

4. go185GBAtemp Regular

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Jun 18, 2006
Plug it into a calculator?

5. SonicslasherIn Law we trust.

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Dec 5, 2005
Richmond, VA
divide by zero?

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Apr 21, 2006

7. joemommasfatMember

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Oct 17, 2006
just like (2^3)^4 = 2^12

(2^sqrt(2))^sqrt(18) = 2^sqrt(36) = 2^6

in general (a^b)^c = a^(b*c)

8. cheesyPOOF5GBAtemp Fan

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Apr 21, 2006
Wow, thanks. That makes a lot of sense.

9. rhyguyGBAtemp Maniac

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Jul 21, 2007
Melbourne
Warning: Spoilers inside!

10. FAST6191Techromancer

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Nov 21, 2005
joemommasfat's method is correct but I suggest you learn the "power laws" as that is what this seems to want to teach.

2^2*2^2=2^4 aka a^x.a^y = a^(x+y)
You might like to think of this for the original purpose it was designed for.
Mathematicians and everyone really is lazy so if something can be written in shorthand it will, not to mention a large group of letters can be very confusing at a glance.
so a.a is written as a^2
a.a.a is written as a^3
a.a.a.a is written as a^4

divided by you take instead of adding a^x/a^y = a^(x-y) (instead you might like to think of it by doing the old method of if you have a divide put it 1/number and multiply it instead and when you know 1/a = a^-1 is becomes a bit easier)

square numbers are inverse powers
i.e. square root of 2 is 2^1/2

power on power gets multiplied
(2^2)^2
=2^4

hope you get it sorted.