[iOS] iOS 9.2-9.3.3 Semi-Tethered Jailbreak Released!

drewby

Well-Known Member
OP
Member
Joined
Dec 29, 2015
Messages
674
Trophies
1
Age
22
Location
Virginia, USA
Website
www.instagram.com
XP
1,332
Country
United States
Details [taken from iDownloadBlog.com]:
"The Pangu Team released a jailbreak Sunday morning that is capable of jailbreaking iOS 9.2 to iOS 9.3.3 devices. Only compatible with 64-bit devices so far, the jailbreak is of the semi-untether kind, meaning a piece of software must be run on the device every time it is rebooted to be put back in a jailbroken state.

The tool is currently available in Chinese only, but should be available in English soon.

On its website, Pangu notes that this jailbreak will allow users to jailbreak their devices “on demand,” a somewhat unusual term when it comes to jailbreaking. Pangu explains that the jailbreak can easily be removed simply by rebooting the device. To re-jailbreak the device, the user will have to run the PP app that was installed on the device during the jailbreak process.

Once rebooted, there is no visible track of a jailbreak on your device. After running the PP app, your device will come back in its jailbreak glory, with all tweaks and packages back on the device. Again, this is an unusual situation, but it’s better than nothing."

This jailbreak only works on 64-bit devices, so sorry 4s, 5, and 5c users.

EDIT: Pangu has confirmed they are updating the jailbreak overnight to improve stability with jailbreak installation. If you are unable to install the jailbreak, wait until the tool is updated since it may be fixed overnight.
 
Last edited by drewby,
  • Like
Reactions: Chary

drewby

Well-Known Member
OP
Member
Joined
Dec 29, 2015
Messages
674
Trophies
1
Age
22
Location
Virginia, USA
Website
www.instagram.com
XP
1,332
Country
United States
While I was waiting for this I'll wait for a permanent jailbreak.
Personally, I would jailbreak now. You only have to run an app to restore the jailbreak and all of your previously installed tweaks
 
Joined
Apr 13, 2010
Messages
1,135
Trophies
1
Website
www.google.com
XP
1,214
Country
United Kingdom
its pangu and you can just use a dummy email and password
True, but they've been getting away with compromising security of their users for a while now. I know they're the only jailbreaking team left, but that still does not justify this requirement of having to input your Apple ID. If anyone wants to use this, they should just create a new Apple ID, and input the details.

@Drew That Gamer Yes, but many people just created a new Apple account to jailbreak.
 
Last edited by insidexdeath,

drewby

Well-Known Member
OP
Member
Joined
Dec 29, 2015
Messages
674
Trophies
1
Age
22
Location
Virginia, USA
Website
www.instagram.com
XP
1,332
Country
United States
True, but they've been getting away with compromising security of their users for a while now. I know they're the only jailbreaking team left, but that still does not justify this requirement of having to input your Apple ID. If anyone wants to use this, they should just create a new Apple ID, and input the details.

@Drew That Gamer Yes, but many people just created a new Apple account to jailbreak.
Well, I put in my actual Apple ID. Shit. Good thing I'm under 18, so I can just leech of my parents' Apple ID if mine gets hacked :)
 
Joined
Apr 13, 2010
Messages
1,135
Trophies
1
Website
www.google.com
XP
1,214
Country
United Kingdom
Well, I put in my actual Apple ID. Shit. Good thing I'm under 18, so I can just leech of my parents' Apple ID if mine gets hacked :)
It's not about it being hacked, it's the details inside of your account, such as home address, and credit card details.

This jailbreak is not worth all this trouble for me, and I never really minded stock iOS. So I'll pass unless they remove the Apple ID requirement.
 
  • Like
Reactions: cearp

cearp

瓜老外
Developer
Joined
May 26, 2008
Messages
8,721
Trophies
2
XP
8,471
Country
Tuvalu
32bit devices arguably shouldn't be running these latest fws anyway, i read they run much better when they are lower than ios 9, although i don't have a 32bit device myself.
i will update from my current jailbreak and jailbreak again now because, we don't know when apple will stop signing 9.3.3 and when there will be a 'better' jailbreak.
once you are jailbroken on 9.3.3 you can still return to stock, using cudia impactor, hoping it still works!
 

cearp

瓜老外
Developer
Joined
May 26, 2008
Messages
8,721
Trophies
2
XP
8,471
Country
Tuvalu
I've always wondered, what's the advantages of having a jailbroken iOS device compared to an Android device (rooted and unrooted)?
that is just an ios vs android thread, find them! i bet there are loads of websites for that.
but if you like extras and more customization, piracy etc, jailbreaking is good fun.
 

drewby

Well-Known Member
OP
Member
Joined
Dec 29, 2015
Messages
674
Trophies
1
Age
22
Location
Virginia, USA
Website
www.instagram.com
XP
1,332
Country
United States
I've always wondered, what's the advantages of having a jailbroken iOS device compared to an Android device (rooted and unrooted)?
Some people like to have the iOS firmware for various reasons, but also want the freedom of Android.
 

raulpica

With your drill, thrust to the sky!
Former Staff
Joined
Oct 23, 2007
Messages
11,056
Trophies
0
Location
PowerLevel: 9001
XP
5,716
Country
Italy
Some people like to have the iOS firmware for various reasons, but also want the freedom of Android.
I had a really good time with a jailbroken iPhone 4 since I could do low-level stuff which is given for granted on Android (filesystem access, cheating in freemium gaems, etc). It was back in the time when we had proper hackers in the iPhone scene (JailbreakMe, greenp0ison, etc). I'd not touch this jailbreak with a 10-foot pole. My phone is filled with sensitive shit and there's no way I'm going to give all my data to a shady team like Pangu is.

On the other hand I'd never use an iOS device without Jailbreak on it, but that's what Android is for :P
 
  • Like
Reactions: Chary

Site & Scene News

Popular threads in this forum

General chit-chat
Help Users
    Xdqwerty @ Xdqwerty: