yes,The 3 and 4 pins of the flexible circuit board are connected together
The pull-down resistor keeps the gate of the FET low in the default state, and if there is no resistance, the default state of the gate of the FET is high-impedance, which may cause the FET to be turned on until it burns
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It is capacitors
Use a multimeter to measure whether the 1V power supply of the CPU has been shorted to GND, if it is short-circuited, it is a fault, and under normal circumstances, there should be a resistance value of several hundred ohms
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The resistance value of the pull-down resistor is about 1~10KΩ.
Are there specific points i can test that at? I'm reading 15 or so ohms across the capacitor with the mosfet on.
Also, when soldering the wires for dat0 et al; it seems like there are pairs of solder pads. Is it okay to solder both, or should only one of those be soldered?
The easiest way is to measure whether the resistance across the capacitor is 0Ω, or use a multimeter buzzer to see if it rings
The D0 pin only needs to be soldered in one set, and EMMC needs to solder a total of 4 pins
d0、cmd、rst、clk
Okay, the capacitor probably isnt shorted. I have a switch lite btw. What i mean by pairs is that there are two contacts highlighted for D0, CMD and CLK in the pinout_lite diagram.
The two contacts are internally connected/
When soldering, only use the connection where you think is most convenient.
You can buy an rp2040-zero and flex ribbon cables from aliexpress
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